Question

The area of a square field is 5184 metersquare . A rectangular field, whose length is twice its
breadth, has its perimeter equal to the perimeter of the square field. Find the area
of the rectangular field. please answer if you know and answer according to chapter square and square roots of class 8 th​

Answer 1

Answer:

The area of the square field = 5184 sq m. Each side of the square field = 5184^0.5 = 72 m. Perimeter of the square field = 4*72 = 288 m.

Step-by-step explanation:

IF THIS WAS THE ANSWER THEN MARK THIS THE BRAINLIEST AND FOLLOW ME..

Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

The area of a square field is 5184 m². A rectangular field, whose length is twice it's breadth, has its perimeter equal to the perimeter of the square field.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The area of the rectangular field.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

Let the side of square be r

We know that formula of the area of square :

$\boxed{\bf{Area=Side\times Side}}}}$

$\longrightarrow\sf{r\times r=5184m^{2} }\\\\\longrightarrow\sf{r^{2} =5184m^{2} }\\\\\longrightarrow\sf{r=\sqrt{5184m^{2} } }\\\\\longrightarrow\sf{\blue{r=72\:m}}$

$\boxed{\bf{Perimeter=4\times Side}}}}$

$\longrightarrow\sf{4\times 72 m}\\\\\longrightarrow\sf{\blue{288m}}$

A/q

We know that formula of the perimeter of rectangle :

$\boxed{\bf{Perimeter=2(length+breadth)}}}}$

We have;

• Length of rectangle be 2b
• Breadth of rectangle be b

Then;

$\longrightarrow\sf{2(2b+b)=288}\\\\\\\longrightarrow\sf{2(3b)=288}\\\\\\\longrightarrow\sf{6b=288}\\\\\\\longrightarrow\sf{b=\cancel{\dfrac{288}{6} }}\\\\\\\longrightarrow\sf{\blue{b=48\:m}}$

Thus;

• Length of rectangle = 2b = (2 × 48)m = 96 m.
• Breadth of rectangle = b = 48 m.

Now;

$\boxed{\bf{Area=Length\times breadth\:\:\:\:(sq.unit)}}}}$

$\longrightarrow\sf{Area=(96 \times 48 )m^{2} }\\\\\longrightarrow\sf{\blue{Area=4608m^{2} }}$

Thus;

The area of rectangle is 4608 m² .