Question

The area of a square field is 5184m find the area of a rectangularpfield whose perimeter is equal to the perimeter of square field and whose length is twice of its bredth

Answer 1

Area of sq. field = 5,184m²

Side of sq. field
$= \sqrt{5184} m \\ = 72m$
Perimeter of sq. field = (4×72)m = 288m


♦ Perimeter of sq. = Perimeter of rec. ♦


Let the breadth be x
So, the length be 2x

A.T.Q.

2(2x+x) = 288

=> 2(3x) = 288
=> 6x = 288
=> x = 288/6
=> x = 48

Breadth = x = 48m
Length = 2x = 2×48 = 96m


♢ Area of rec. field = ( length×breadth )

= (96×48)m²
= 4608m²


Answer —

Area of rectangular field is 4608m²

Answer 2

Here is your solution

Given :-

Area of square = 6889 m^2

we have to find perimeter of square =?

Now

Area of square = side^2

=>5184 m^2 = side^2

=>72m =side of square

Now

perimeter of square => 4× side .
=> 4×72=288m

Now,

Let,
The breadth of rectangle be x

Then the length be 2x

As we know that,

 perimeter of a rectangle =2(length+breadth)

And, perimeter of square = perimeter of rectangle = 288m 

288 = 2(x + 2x)

288/2 = 3x

144 = 3x

144/3 =x

48 = x

Then,

breadth of rectangle = x = 48 m 

and length of rectangle = 2x = (2×48) = 96m 

Now,

Area of rectangle = length×breadth

Here,

Area of rectangle =  48×96 

Area of rectangle =4608 m^2

Hopeit helps you