Math, asked by saazpreetkaur, 4 months ago

The area of a square field is 5184msq. A rectangular field , whose length is twice its breadth , has its perimeter equal to the perimeter of the square field. Find the area of the rectangular field . ??

Answers

Answered by Anonymous
19

Question:-

The area of a square field is 5184m². A rectangular field , whose length is twice its breadth , has its perimeter equal to the perimeter of the square field. Find the area of the rectangular field . ??

Answer:-

  • The area of rectangle is 4608 m².

To find:-

  • Area of rectangle

Solution:-

  • Area of square = 5184 m²

As we know,

 \large{ \boxed{ \mathfrak{area =  {side}^{2} }}}

Now,

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \:  {side}^{2}  = 5184}

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: side =  \sqrt{5184} }

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: side = 72}

  • The side of square is 72 m

  • Perimeter of square = perimeter of rectangle

As we know,

 \large{ \boxed{ \mathfrak{perimeter \: of \: square = 4 \times side}}}

Now,

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: perimeter = 4 \times 72}

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: perimeter = 288}

  • The perimeter of square is 288 m

In rectangle,

  • Length = 2x
  • Breadth = x
  • Perimeter = 288

As we know,

 \large{ \boxed{ \mathfrak{perimeter = 2(l + b)}}}

Where,

  • l = length of rectangle
  • b = breadth of rectangle

Then,

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: 2(2x + x) = 288}

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: 3x =  \frac{288}{2} } \\

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: 3x = 144}

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: x =  \frac{144}{3} } \\

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: x = 48}

  • The value of x is 48 m
  • Length = 2x = 2×48 = 96 m
  • Breadth = x = 48 m

We have to find out the area of rectangle

As we know,

 \large{ \boxed{ \mathfrak{area \:  = l \times b}}}

Where,

  • l = length of rectangle
  • b = breadth of rectangle

According to question,

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: area = 96 \times 48}

 \large{ \tt :  \implies \:  \:  \:  \:  \:  \:  \:  \: area = 4608}

Hence,

  • The area of rectangle is 4608 .
Answered by Anonymous
8

\bf  {\underline {\underline{✤QƲЄƧƬƖƠƝ}}}

The area of a square field is 5184m². A rectangular field , whose length is twice its breadth , has its perimeter equal to the perimeter of the square field. Find the area of the rectangular field ?

\bf  {\underline {\underline{✤ ƛƝƧƜЄƦ}}}

➡Area of rectangular field is 2888m².

\bf  {\underline {\underline{✤ ƓƖƔЄƝ}}}</p><p>

  • Area of square field = 5184m²

\bf  {\underline {\underline{✤ ƬƠ  \:  \:  ƇƛLƇƲLƛƬЄ}}}

  • Area of rectangular field

\bf  {\underline {\underline{✤ ƑƠƦMƲLƛ  \:  \: ƬƠ  \: ƁЄ \:  \:  ƲƧЄƊ}}}

Area of Square =

 \bf {side}^{2}

Perimeter of Square =

 \bf4 \times side

Area of rectangle =

 \bf \: length \times breadth

Perimeter of rectangle =

 \bf2(lenght + breadth)

\bf  {\underline {\underline{✤ SƠԼƲƬƖƠƝ}}}

 \bf Area \:  of  \: Square \: field =   {5184m}^{2}

 \bf  \implies  {side}^{2}  = 5184

 \bf  \implies side =  \sqrt{5184}

 \bf  \implies side = 72m

 \bf Perimeter  \: of \:  Square  = 4 \times side

 \bf  = 4 \times 72

 \bf = 288m

According to question,

Perimeter of square = Perimeter of rectangle

 \bf Perimeter  \: of  \: rectangle = 2(l + b)

 \bf \implies 288 = 2(2x + x)

 \bf \implies 288 = 2 \times 3x

 \bf \implies 288 \div 2 = 3x

 \bf \implies 114 = 3x

 \bf \implies 3x = 114

 \bf \implies x = 114 \div 3

 \bf \implies x = 38m

  • Breadth of field = x = 38m
  • Length of field = 2x = 2 × 38 = 76m

 \bf area \: of \: rectangular \: field = l \times b

 \bf = 38 \times 76

 \bf = 2888 {m}^{2}

Therefore, Area of rectangular field is 2888m².

 \bf \pink{hope \: } \purple{it \: } \blue{helps \: } \red{uh..}

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