Math, asked by bs3732007, 5 hours ago

the area of a square field is 60025 m a mam cycles along its boundary at 18km/he in how much time will he return to the starting point ?

Answers

Answered by vanshsati
1

Answer:

Answer:

He will return to starting point in 196 seconds.

Step-by-step explanation:

Area of square field = 60025 sq.m.

Area of square = Side ^2Side

2

So, 60025=Side ^260025=Side

2

\sqrt{60025}=Side

60025

=Side

245=Side245=Side

Since we are given that he cycles along the boundary of field

So, Perimeter of square field =4 \times Side4×Side

Perimeter of square field =4 \times 2454×245

Perimeter of square field =980 m980m

So, Total distance = 980 m

Speed = 18 km/h =18 \times \frac{5}{18} =5 m/s18×

18

5

=5m/s

Time =\frac{Distance}{Speed}Time=

Speed

Distance

Time =\frac{980}{5}Time=

5

980

Time =196Time=196

Hence he will return to starting point in 196 seconds.

Answered by Anonymous
58

Answer:

  • 3 mins 16 seconds.

Step-by-step explanation:

As per information provided in the given question, We have :

  • Area of a square field = 60025m²
  • Speed of cycling = 18km/h

We are asked to calculate the time to return back.

In order to calculate the time to return back by the man, firstly we need to convert 18km/h in m/s. Then, we will find the perimeter of the square field. In order to do it, We will find side. So,

Converting km/h into m/sec :

\longmapsto \rm \dfrac{1000 \times 18}{60 \times 60}\\

\longmapsto \rm \dfrac{10\times 18}{6 \times 6}\\

\longmapsto \rm \dfrac{180}{36}\\

\longmapsto \rm 5 \: m/s\\

Finding side of square :

Given, area = 60025 m²

  • Let us assume side as a.

\longmapsto \rm {(a)}^{2} = 60025\\

\longmapsto \rm a=  \sqrt{60025}\\

\longmapsto \rm a = 245\\

Finding perimeter of square :

\longmapsto \bf Perimeter_{(square)} = 4 \times s \\

\longmapsto \rm Perimeter_{(square)} = 4 \times 245 \\

\longmapsto \rm Perimeter_{(square)} = 980 \\

∴ Perimeter of the square is 980.

Finding how much time will he return to the starting time :

\longmapsto \bf Time = \dfrac{Distance}{Speed}\\

\longmapsto \rm \dfrac{980}{5}\\

\longmapsto \rm 196 \:  seconds\\

∴ He will return back to the starting point in 3 minutes 16 seconds.

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