Question

The area of a square field is 60025 m². Kapil cycles along its boundary at
5 m/s. In how much time will he return to the starting point?​ plz can u include statements too??​

Answer 1

Step-by-step explanation:

area of a square field a²=60025

a=245

perimeter is = to 4A

4×245

=980

if he moves with a constant velocity of 5mper second

then speed =distance/time

5m/s=980/t

t=980/5

t=196 seconds or 3minutes 16 seconds