The area of a square field is 60025 square metre a man cycles along its boundary at 18 kilometre per hour in how much time will he return to the starting point
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let 1 side of the square field be x
side^2=area of square (formula for area of square)
x^2=60025 (putting the values according to the formula)
x = underroot 60025
x = 245
side = 245metre
perimeter of square field is 4 times its side
therefore 245x4=980m
speed of man= 18km/hr (convert into m/s)
18km/hr x 1000m/(60x60)sec=18000m/3600sec=5m/sec (bringing it to its simplest form)
speed=distance/time
5m/sec=980/time (make time the subject of the equation)
time=980/5
time=196 seconds or 3 minute 16 seconds
i hope if i m correct and it helps you
side^2=area of square (formula for area of square)
x^2=60025 (putting the values according to the formula)
x = underroot 60025
x = 245
side = 245metre
perimeter of square field is 4 times its side
therefore 245x4=980m
speed of man= 18km/hr (convert into m/s)
18km/hr x 1000m/(60x60)sec=18000m/3600sec=5m/sec (bringing it to its simplest form)
speed=distance/time
5m/sec=980/time (make time the subject of the equation)
time=980/5
time=196 seconds or 3 minute 16 seconds
i hope if i m correct and it helps you
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