The area of a square field is 60025sq. m.A man cycles along its boundary at 18 km per hr. In how much time will be return at the starting point.
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as here the side of field will come 245m because 245 is square root of 60025 now if the man is cycling at a speed of 18 km/hr. which is 5m/s then he will come back to starting point in time
we know that distance he has to cover is 245×4 =980 mtr. and hence time =distance upon speed
hence time=980/5=196 seconds
we know that distance he has to cover is 245×4 =980 mtr. and hence time =distance upon speed
hence time=980/5=196 seconds
hrshpatidar:
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GOOD AFTERNOON
Hlo Frnd here is your answer--
Area of square field = 60025 m²
Area of square field = side²
side² = 60025 m²
side = √60025 m²
side = 245 m
Perimeter of square field = 4 * side
= 4 * 245 m
= 980 m
Speed = 18 km / hr
= 18 km / 1 hr * 1 / 3600 * 1000 / 1
= 18 * 1000 m / 3600 sec
= 5 m / sec
Speed = Distance / Time
Distance = 980 m
Speed = 5 m / sec
Time = ?
5 = 980 / Time
Time = 980 / 5
Time = 196 sec
HAVE A GOOD DAY
Hlo Frnd here is your answer--
Area of square field = 60025 m²
Area of square field = side²
side² = 60025 m²
side = √60025 m²
side = 245 m
Perimeter of square field = 4 * side
= 4 * 245 m
= 980 m
Speed = 18 km / hr
= 18 km / 1 hr * 1 / 3600 * 1000 / 1
= 18 * 1000 m / 3600 sec
= 5 m / sec
Speed = Distance / Time
Distance = 980 m
Speed = 5 m / sec
Time = ?
5 = 980 / Time
Time = 980 / 5
Time = 196 sec
HAVE A GOOD DAY
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