Question

THE AREA OF A SQUARE FIELD IS 7744 sq.METRES.FIND ITS PERIMETER

Answer 1

area of square =(s)^2
7744=s^2
therefore,s=√7744
s=88
perimeter of square =4a
=4×88
=352
perimeter of square=352

Answer 2

let the side be x
area of field =7744sq. m
7744sq.m=side sq.
7744 sq.=x sq.
x=7744 underoot
x=88
perimeter=4*side
4*88
=352m