Question

The area of a square Field is 8649m2. A rectangular field whose length is twice its breadth and has its perimeter equal to the perimeter of the square field . Find the area of the rectangular field

Answer 1

the area of square field =8649msq.

we know that area of square field= side^2

A^2= 8649

so,A = √8649.

= 93
now in 2nd condition,

given a rectangular field whose length=2X
and breadth = X



now the perimeter of square= 4 × one side

so, 4× 93= 372m

372= 2(2X+x)

372= 4x+2x= 6x

X=372/6= 62

now,length = 2x= 2×62= 124

and breadth= 62

so the area of rectangle= L×B= 124×62=7688msq.

hope it help you

Answer 2

let side of square be x ..
then , x² = 8649
so, x= 93
now , perimeter of square= 372

side of rectangle=
length = 2y
b= y
perimeter = 372
2(y+2y)= 372
3y = 186
y= 62
area of rectangular field==
62×124
== 7688