Question

The area of a square frame is 2061 cm2. Find the perimeter of the frame

Answer 1

Given :

• The area of a square frame is 2061 cm² .

To find :

• Perimeter of the frame.

Solution :

• Area = 2061 cm²

Formula Used :-

${\boxed{\bold{Area\:of\: square=a^2}}}$

Where,

• a = Side of square .

According to the question :-

$\to\sf{a^2=2061}$

$\to\sf{a=\sqrt{2061}}$

$\to\sf{a= 45.4}$

• Side of square = 45.4 cm

Formula Used :-

${\boxed{\bold{Perimeter\:of\: square=4a}}}$

Perimeter of the square frame,

→ 4 × a

→ 4 × 45.4 cm

→ 181.6 cm .

Therefore, the perimeter of the square frame is 181.6 cm.

__________________

Some formulas :-

★ Perimeter of rectangle = 2( length + Breadth)

★ Area of rectangle = length× Breadth

★ Diagonal of rectangle = √(length ² + breadth ²)

Answer 2

$\underline{\rm Given :}$

• $\small\rm{Area \; of \; square \; frame = 2061 cm^2}$

$\underline\rm To \;Find:$

• $\small\rm Perimeter \; of \; square \; frame$

$\underline\rm {Solution: } \\\\ \sf{Firstly \; finding \; side \; of \; square}\\\\\sf{Area \; of \; square = side^2}\\\\\to \sf 2061 = side^2\\\\ \to \sf side = \sqrt{2061} = \boxed{\bf{45.39}}\\\\\rm Now, \\\\ {\rm Perimeter \;of\; square = 4(side)=4(45.39}\\\\\dag\;\bf\boxed{181.56}$