Question

The area of a square held is 60025² m. A man cycles along its boundary at 18 km/h. In how
much time will be return to the starting point?​

Answer 1

Answer:

He will return to starting point in 196 seconds.

Step-by-step explanation:

Area of square field = 60025 sq.m.

Area of square = Side ^2Side

2

So, 60025=Side ^260025=Side

2

\sqrt{60025}=Side

60025

=Side

245=Side245=Side

Since we are given that he cycles along the boundary of field

So, Perimeter of square field =4 \times Side4×Side

Perimeter of square field =4 \times 2454×245

Perimeter of square field =980 m980m

So, Total distance = 980 m

Speed = 18 km/h =18 \times \frac{5}{18} =5 m/s18×

18

5

=5m/s

Time =\frac{Distance}{Speed}Time=

Speed

Distance

Time =\frac{980}{5}Time=

5

980

Time =196Time=196

Hence he will return to starting point in 196 seconds.