Question

The area of a square is 1600meter square. Find the area of the rectangle whose breadth is the same as that of the square and length is 10m more than its breadth.

Answer 1

the square=A2 side =√1600=40m

breadth of =40m length 40+10=50

area of rectangle =l×b

=40×50

2000m2

Answer 2

$\Large{\underline{\underline{\mathfrak{\bf{Question}}}}}$

The area of a square is 1600meter square. Find the area of the rectangle whose breadth is the same as that of the square and length is 10m more than it's breadth.

$\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$

$\Large{\underline{\mathfrak{\bf{Given}}}}$

• Area of square = 1600 m²
• Breadth of rectangle same as the side of square
• Length is 10 m more that it's breadth

$\Large{\underline{\mathfrak{\bf{Find}}}}$

• Area of rectangle

$\Large{\underline{\underline{\mathfrak{\bf{Explanation}}}}}$

We know,

$\small\boxed{\sf{\:Area_{square}\:=\:(Side)^2}} \\ \\ \\ \small\sf{\orange{\:\:\:\:\:\:\:\:\star{\:Area_{square}\:=\:1600}}} \\ \\ \\ \mapsto\sf{\:1600\:=\:(side)^2} \\ \\ \\ \mapsto\sf{\:(side)\:=\:\sqrt{1600}} \\ \\ \\ \mapsto\sf{\:Side\:=\:40\:m}$

By first condition:-

( Breadth of rectangle same as the side of square )

So,

$\mapsto\sf{\:Breadth_{rectangle}\:=\:side_{square}} \\ \\ \\ \mapsto\sf{\:Breadth_{rectangle}\:=\:40\:m}$

Now, Second condition :-

( Length is 10 m more that it's breadth )

So,

$\mapsto\sf{\:Length_{rectangle}\:=\:Breadth_{rectange}\:+\:10} \\ \\ \\ \mapsto\sf{\:Length_{rectangle}\:=\:40+10} \\ \\ \\ \mapsto\sf{\:Length_{rectangle}\:=\:50\:m}$

Again,

$\small\boxed{\sf{\:Area_{rectangle}\:=\:(Length\times Breadth)}} \\ \\ \\ \mapsto\sf{\:Area_{rectangle}\:=\:(50\times 40)} \\ \\ \\ \mapsto\sf{\:Area_{rectangle}\:=\:2000\:m^2}$

$\Large{\underline{\mathfrak{\bf{Hence}}}}$

• Area of rectangle = 2000 m²