The area of a square is 26200sq m.Find the length of its diagonal
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let the square is ABCD with AC and BD diagonals
let side of square = x metre
diagonal = y metre
in triangle ABC
angle A = 90°
so by Pythagoras theorem
x² + x² = y²
2x²= y²
y=x√2
x=y/√2 metre
area of square = (side)² = x² = (y/√2)²
26200 = y²/2
y²= 26200×2
y²=52400
y=√52400
y=10√524
y=10×4√131
so, length of the diagonal is 40√131 metre
let side of square = x metre
diagonal = y metre
in triangle ABC
angle A = 90°
so by Pythagoras theorem
x² + x² = y²
2x²= y²
y=x√2
x=y/√2 metre
area of square = (side)² = x² = (y/√2)²
26200 = y²/2
y²= 26200×2
y²=52400
y=√52400
y=10√524
y=10×4√131
so, length of the diagonal is 40√131 metre
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