Question

The area of a square is 289 cm sq find its perimeter& length of diagonal

Answer 1

Step-by-step explanation:

area of square= a^2

area of a square= 289

a^2 = 289

a = √289=17cm

perimeter of square= 4a

= 4*17

= 68 cm

Diagonal of square= √2a

= √2*17

= 17√2 cm

Hope it helps you..........

Answer 2

The perimeter and the length of diagonal would be 68 cm and 17√2 cm resp.

Step-by-step explanation:

Since we have given that

Area of square = 289 cm. sq.

We need to find the side of square first:

So, the side of square would be

$Area=Side^2\\\\\sqrt{Area}=Side\\\\\sqrt{289}=Side\\\\17\ cm=Side$

Perimeter of a square would be

$4\times side=4\times 17=68\ cm$

and the length of diagonal would be

$\sqrt{2}a=\sqrt{2}\times 17=17\sqrt{2}\ cm$

Hence, the perimeter and the length of diagonal would be 68 cm and 17√2 cm resp.

# learn more:

The area of a square is 81 cm sq find the perimeter and length of its diagonal​

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