Math, asked by rishupandit789pe216y, 1 year ago

the area of a square is 3364 sq. cm. what is the ratio of the perimeter of the square to that of a rectangle if the length of the rectangle is thrice the side of the square and the breadth is 18 m less than the side of the square?

Answers

Answered by TheLostMonk
1
"here is your solution"

"hope it helps"
Attachments:

rishupandit789pe216y: thanks bhai
TheLostMonk: welcome
Answered by TooFree
3

Area of the square = 3364 cm² (Given)


Find the length of the square:

Area = Length²

Length² = 3364

Length = √3364

Length = 58 cm


Find the perimeter of the square:

Perimeter = 4 x Length

Perimeter = 4 x 58 = 232 cm


Find the length of the rectangle:

Length = 3 x 58 = 174 cm


Find the breadth of the rectangle:

Breadth = 58 - 18 = 40 cm


Find the perimeter of the rectangle:

Perimeter = 2( Length + Breadth)

Perimeter = 2(174 + 40) = 428 cm


Find the ratio of perimeter of the square to the rectangle:

Square : Rectangle = 232 : 428

Simplifying by dividing by 4:

Square : Rectangle = 58 : 107


Answer: The ratio is 58 : 107

Similar questions