Question

The area of a square is 49 sq cm A rectangle has the same perimeter as the square. If the length of the rectangle is 9.3 cm , what is its breadth? Also find which has greater area?

Answer 1

Area of square =49cm²
side²=49
side=7
after find its perimeter
so.
perimeter of square =4*side
4*7
28 cm
and
given that perimeter of square =perimeter of ractangle
so
28=2(l+b)
28/2=9.3+b
b=14-9.3
=4.7 cm
after find area of rectangle
l*b
9.3*4.7
=43.71 cm²
so the area of square is greater than the Area of rectangle hope this help u

Answer 2

Here,
Area of square =49 sq. cm
s^2 =49 sq. cm
s=7cm

perimeter of square= 4×7 =28 cm
Here ,perimeter of square and rect. are equal.
so,
perimeter of square = perimeter of rect.
l= 9.3 cm
28cm = 2 (l +b)
28 /2 = 9.3 + b
14-9.3 =b
b=4.7 cm

area of □= 49 sq. cm and area of rectangle = l×b = 43.71 sq. cm

so, □ has a greater area.
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