Question

The area of a square is 49 sq cm A rectangle has the same perimeter as the square. If the length of the rectangle is 9.3 cm , what is its breadth? Also find which has greater area?

Answer 1

Let x be the breadth of the rectangle.
As area of square is 49 cm^2, its side is 7 cm.
Perimeter of square = 28 cm.
Perimeter of rectangle = 2(9.3 + x) = 28 cm
Thus, x = 4.7 cm
Are of rectangle = 4.7 * 9.3 = 43.71 cm^2
Thus, the square has greater area.

Answer 2

let area of square be x^2
and here x^2=49
x=+-7
since length can't be negative so a=7
and we know that
perimeter of  rectangle = perimeter  as square(.given)
length of rectangle =9.3(given)
perimeter of square =4x (where x is the length of side)
plugging in the values
and perimeter of rectangle=2(l+b) where l is length and b is breadth
we get
4x = 2( l + b )  
plugging in the given values we get
4*7=2(9.3+b)
28=18.6+2b
28-18.6=2b
9.4/2=b
b=4.7 
area=l*b
=4.7*9.3
4.7 * 9.3 = 43.71
hence 49>43.71
so square has more area