Question

The area of a square is 49 square centimetres a rectangle has the same perimeter as the square if the length of the rectangle is 9.3 cm what is the breadth also find which has greater area

Answer 1

See in the above photo

Answer 2

$area \: of \: square = 49 {cm }^{2} \\ {(side)}^{2} = 49 \\ taking \: under \: root \: both \: sides - - \\ = > \sqrt{(side) {}^{2} } = \sqrt{49} \\ = > side = 7 \: cm \\ \\ now \: perimeter \: of \: the \: square = 4 \times side \\ = 4 \times 7 \\ = 28 \: cm \\ \\ let \: the \: breadth \: of \: rectangle \: be \: b \\ \\ \: it \: is \: given \: that \: the \: perimeter \: of \\ square \: is \: equal \: to \: the \: perimeter \: \\ of \: rectangle - - \\ \\ perimeter \: of \: rectangle = 2( l+ b) \\ = > 28 = 2(9.3 + b) \\ = > 28 = 18.6 + 2b \\ = > 28 - 18.6 = 2b \\ = > 9.4 = 2b \\ = > \frac{9.4}{2} = b \\ \\ = > \frac{94}{10 \times 2} = b \\ \\ = > 4.7 = b \\ breadth \: of \: rectangle \: is \: 4.7cm\\now\: area\: of\: rectangle=l\times b \\=9.3\times4.7 \\=43.71 cm^2 \\\\thus \:area \:of\: square \:is\: more \:than\: area \:of \:rectangle.\\\\\\ please \: mark \: it \: as \: brainliest.$