The area of a square is 49sq cm.A rectangle has the same peroimete as the square.If the length of the rectangle is 9.3 cm, what is the breadth? Also find which has greater area?
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Area of square= side(square) =49 cmsq.
= 49=7×7 so the side of square is 7 cm.
then perimeter of square=4×side
=4×7=28cmsq.
Given that it is equal to perimeter of rectangle So, 28= 2(l+b)
28= 2(9.3+b)
14=9.3+b
b=4.7
So the area of rectangle= l×b
then 9.3×4.7=43.71
Therefore the area of rectangle is greater than square ..
Thank u
= 49=7×7 so the side of square is 7 cm.
then perimeter of square=4×side
=4×7=28cmsq.
Given that it is equal to perimeter of rectangle So, 28= 2(l+b)
28= 2(9.3+b)
14=9.3+b
b=4.7
So the area of rectangle= l×b
then 9.3×4.7=43.71
Therefore the area of rectangle is greater than square ..
Thank u
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