The area of a square is 49sqcm A rectangle has the same perimeter as the square.If the length of the rectangle is 9.3cm what is breadth? Also find which has greater area
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let breadth be x
Area of square =49
therefore side of square=7cm and perimeter of square=28
Perimeter of rectangle=2(9.3+x)=28
x=4.7
Area=4.7×9.3
area=43.71
therefore area of rectangle has greater area
Area of square =49
therefore side of square=7cm and perimeter of square=28
Perimeter of rectangle=2(9.3+x)=28
x=4.7
Area=4.7×9.3
area=43.71
therefore area of rectangle has greater area
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Let each side of square be a cm.
Area of square=a*2
49=a*2
√49=a
a=7cm.
perimeter of square= perimeter of rectangle
4a=2(l+b)
4×7=2(9.3+b)
28=18.6+2b
2b=28-18.6
2b=9.4
b=4.7
breadth of rectangle=4.7
Area of rectangle=4.7×9.4=43.71
hence square has more area
Area of square=a*2
49=a*2
√49=a
a=7cm.
perimeter of square= perimeter of rectangle
4a=2(l+b)
4×7=2(9.3+b)
28=18.6+2b
2b=28-18.6
2b=9.4
b=4.7
breadth of rectangle=4.7
Area of rectangle=4.7×9.4=43.71
hence square has more area
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