Math, asked by Kimneichangsan23, 3 months ago

the area of a square is 64 cm 2 a rectangle has the same perimeter as the square if the length of the rectangle is 11 cm find its breadth

Answers

Answered by Anonymous
4
AnSwer -:

Breadth of Rectangle = 5 cm

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______________________________

Step by Step Explanation -:


Area of square-:

“A = S x S”

Perimeter of a square-:

“P= 4 x S”

S = length of side of a square

P = Perimeter

A = Area

Perimeter of a Rectangle-:

“P= 2(l+b)”

P = Perimeter

L = length

B = breadth

______________________________

Given ,

Area of square = 64 cm^2 = side x side =

(Side)^2

Length of Rectangle = 11 cm

To find,

Breadth of Rectangle.

______________________


Area of square = side x side= (side)^2

Side of a square = ??

Area of square = 64 cm^2

(Side)^2 = 64 cm^2

Side = ✓64

Side = 8 cm

Side of a square = 8cm


Perimeter of square 4 x s

Side of a square = 8 cm

4 x 8 =

= 32 cm

Perimeter of square = 32 cm

According to the question,

Perimeter of square = Perimeter of

Rectangle

Then ,

Formula of perimeter of rectangle-:

2(l+b)

Perimeter of rectangle-: 32 cm

Length of Rectangle-: 11 cm = l

Breadth of Rectangle-: ?? = b

2 (11 + b) = 32 cm

22 + 2b

2b = 32 - 22

2b = 10

B = 10/2

B= 5

Therefore,

Breadth of Rectangle = 5 cm

_____________________________

Answered by Anonymous
11

Question:-

the area of a square is 64 cm² a rectangle has the same perimeter as the square if the length of the rectangle is 11 cm find its breadth

Answer:-

  • The breadth of rectangle is 5 cm.

Solution:-

  • Area of square = 64 cm²

 \purple{ \underline{ \underline{ \mathfrak{ \large{ \pink{area =  {side}^{2} }}}}}}

 \large{ \tt : \implies \:  \:  \:  \:   {side}^{2}  = 64}

 \large{ \tt : \implies \:  \:  \:  \:  side =  \sqrt{64} }

 \large{ \tt : \implies \:  \:  \:  \:  side = 8 \: cm}

  • The side of square is 8 cm

 \green{ \underline{ \underline{ \mathfrak{ \large{ \purple{perimeter = 4 \times side }}}}}}

 \large{ \tt : \implies \:  \:  \:  \:  perimeter = 4 \times 8}

 \large{ \tt : \implies \:  \:  \:  \:  perimeter =32 \: cm}

  • Perimeter of square = Perimeter of rectangle
  • Length of Rectangle = 11 cm

 \orange{ \underline{ \underline{ \mathfrak{ \large{ \green{perimeter = 2(l + b)}}}}}}

 \large{ \tt : \implies \:  \:  \:  \:  2(11 + b) = 32}

 \large{ \tt : \implies \:  \:  \:  \: 11 + b =  \frac{32}{2} } \\

 \large{ \tt : \implies \:  \:  \:  \: 11 + b = 16}

 \large{ \tt : \implies \:  \:  \:  \: b = 16 - 11}

 \large{ \tt : \implies \:  \:  \:  \: b = 5}

  • The breadth of rectangle is 5 cm.
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