the area of a square is given by 9x^2+54xy+81y^2.find the side of the square
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area of the square = 9x²+54xy +81y²
side*side = (3x)² +2*3x*9y +(9y)²
(side)²= (3x+9y)² [ ∵(a+b)²=a²+2ab+b²]
therefore
side of the square = 3x+9y
side*side = (3x)² +2*3x*9y +(9y)²
(side)²= (3x+9y)² [ ∵(a+b)²=a²+2ab+b²]
therefore
side of the square = 3x+9y
savleen:
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