Question

The area of a square is given by 9x² +54xy + 81y. Find the side of the square.​

Answer 1

Answer:

$\red {Side \: of \:the \:square } \green {=3(x+3y)}$

Step-by-step explanation:

There may be mistake in last term . It may be like this 81y².

$Let \: side \: of \:the \: share = a$

$Area \: of \:the \: square = 9x^{2}+54xy+81y^{2}$

$\implies a^{2}= (3x)^{2} +2\times 3x\times 9y +(9y)^{2}$

$\implies a^{2} = (3x+9y)^{2}$

$\implies a = 3x+9y= 3(x+3y)$

Therefore.,

$\red {Side \: of \:the \:square } \green {=3(x+3y)}$

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