Question

The area of a square is one fifth the area of a rectangle.The area of the rectangle is 1620sq.Cm and length of the rectangle is 54 cms.What is the difference between the side of the square and bredth of the rectangle

Answer 1

Given that,

Area of rectangle = 1620 cm²

and length = 54 cm

so,

breadth = 1620/54

so,

breadth = 30 cm

Now,

also given that,

area of square one fifth of area of rectangle

so,

area of square = 1620/5

= 324 cm²

also,

for square,

side² = 324

side = 18 cm

Now,

difference between side of square and breadth of rectangle

= 30 - 18

= 12 cm

so,

difference between side of square and breadth of rectangle = 12 cm

Answer 2

$\large\underline{ \underline{ \sf \: Solution : \: \: \: }}$

Given ,

$\star$Area of rectangle = 1620 cm²

$\star$Length = 54 cm

$\star$So , Breadth = 1620/54 i.e 30 cm

$\star$The area of square is one fifth of the area of rectangle

So ,

$\fbox{ \sf \red {\:Area \: of \: square = \frac{1}{5} × Area \: of \: rectangle </p><p> \: }}$

$\implies \sf {(side)}^{2} = \frac{1620}{5} \\ \\\implies \sf {(side)}^{2} </p><p>= 324 \\ \\ \implies \sf</p><p>side = 18 \: cm$

Now , we have to find difference between the side of the square and breadth of the rectangle , So ,

$\fbox{ \sf \red {Bredth \: of \: the \: rectangle - side \: of \: the \: Square}}$

$\sf \implies 30 - 18 \\ \\ \sf \implies</p><p></p><p>12 \: cm$

$\therefore$12 cm is the required value