Question

The area of a square is (x2 - 6x +9) sq. units. Find its perimeter.​

Answer 1

$area \: of \: square= \: {x}^{2} −6x+9 \\ area \: of \: square= {side}^{2} \\ {x}^{2} −6x+9= {side}^{2} \\ side= \sqrt{ {x}^{2}−6x+9 } \\ =  \sqrt{ {x}^{2} −3x−3x+9} \\ = \sqrt{x(x−3)−3(x−3)} \\</p><p>$

$side = \sqrt{ {(x - 3)}^{2} } \\ side = (x - 3)$

perimeter of square = 4 x side

= 4 x (x-3)

= 4x -12