Question

THE AREA OF A SQUARE OF A RECTANGLE. IT'S LENGTH IS 40 CM AND BREADTH IS 22 CM . IF THE SAME WIRE IS REBENT IN THE SHAPE OF SQUARE, WHAT WILL BE THE MEASURE OF EACH SIDE ALSO FIND WHICH SHAPE ENCLOSE MORE AREA​

Answer 1

I see your photo instead of the question...LOL.

I didn't get the question anyway

Answer 2

Answer:

Step-by-step explanation:

Given A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is re bent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

As given length of rectangle is 40 cm and breadth is 22 cm. Let the side of square be x cm.

Now the wire is bent in the shape of a square.

So perimeter of square = perimeter of rectangle

    4 x = 2(l + b)

    4 x = 2(40 + 22)

    4 x = 2 x 62

     x = 31 cm

Side of square x = 31 cm

Now area of rectangle = l x b = 40 x 22 = 880 sq cm

Again area of square = x^2 = (31)^2 = 961 sq cm

So 961 - 880 = 81 sq cm

We see that area area of square encloses more area by 81 sq cm