Question

The area of a square playground
is 296.48 square metre. Find the length if its
side correct to three decimal places.​

Answer 1

Answer:

296.48 square meter

Step-by-step explanation:

Given

Area of square playground= 296.48m²

Find out

Find the length of its side correct to three decimal places.

Solution

As we know that

★ Area of square = side × side ★

*Let the side be a*

➟ Area of square = 296.48

➟ a × a = 296.48

➟ a² = 296.48

➟ a = √296.48

➟ a = 17.218m

Hence, the side of square playground is 17.218m

Additional Information

Area of rectangle = length × breadth

Perimeter of rectangle = 2(l+b)

Area of circle = πr²

Perimeter of circle = 2πr

Perimeter of square = 4 × side

Answer 2

Given: The area of the square playground is 296.48m².

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Need to find: The length of its side correct to three decimal places.

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$\underline{\bf{\dag}\frak{\;As\;we\;know\; that\;:}}$

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$\star\;{\boxed{\pink{\frak{Area\;_{(square)}=(Side\times Side)}}}}$

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Therefore,

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$\sf{⇢\;(Side\times Side)=296.48}\\\\\\\sf{⇢\;(Side)^2=296.48}\\\\\\\sf{⇢\;Side=\sqrt{296.48}}\\\\\\⇢\;\underline{\boxed{\purple{\frak{Side=17.218\;m}}}}{\;\bigstar}$

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$\therefore\;{\underline{\sf{Hence,\;the\;length\;of\;its\;side\;is\;{\textsf{\textbf{17.218\;m}}}}.}}$

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$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(Side\times Side) \\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$