Math, asked by Xeyahaider, 3 months ago

The area of a square plot is 1600 m². Find the
length of wire, which can go 4 times around the
boundary of this plot.
(a) 150 m
(b) 200 m
(C) 640 m
(d) 260 m​

Answers

Answered by Sauron
129

Answer:

Option (C) 640 m

The length of the wire is 640 m.

Step-by-step explanation:

Given:

Area of the square plot = 1600 m²

To find:

The length of the wire which can go 4 times around the boundary of the plot.

Solution :

Area of the Square = Side × Side

Let the side be y

\sf{\longrightarrow} \: y \times y = 1600

\sf{\longrightarrow} \: {y}^{2}  = 1600

\sf{\longrightarrow} \:y =  \sqrt{1600}

\sf{\longrightarrow} \:y = 40

Side = 40 m

Perimeter of square = Side × 4

\sf{\longrightarrow} \:40 \times 4

\sf{\longrightarrow} \:160 \:

Perimeter = 160 m

The wire needs to go around the boundary 4 times.

Length of the wire = Perimeter × 4

\sf{\longrightarrow} \:160 \times 4

\sf{\longrightarrow} \:640

Length of the wire = 640 m

Therefore, the length of the wire is 640 m.


rsagnik437: Awesome! :D
Sauron: <3
Answered by Anonymous
135

Answer:

Given :-

  • The area of a square plot is 1600 m².

To Find :-

  • What is the length of wire which can go 4 times around the boundary of plot.

Solution :-

Given :

  • Area = 1600 m².

First, we have to find the side of a square plot,

As we know that,

{\underline{\boxed{\mathcal{\pmb{\quad Area\: of\: Square =\: Side \times Side\quad}}}}}

Then, according to the question,

\sf Side \times Side =\: 1600

\sf {(Side)}^{2} =\: 1600

\sf Side =\: \sqrt{1600}

\sf\bold{Side =\: 40\: m}

Hence, the each side of a square plot is 40 m .

Again, we have to find the perimeter of a square plot,

As we know that,

{\underline{\boxed{\mathcal{\pmb{\quad Perimeter =\: 4 \times Side\quad}}}}}

Given :

  • Side = 40 m

Then,

\sf Perimeter\: =\: 4 \times 40

\sf\bold{Perimeter =\: 160\: m}

Hence, the perimeter of a square plot is 160 m .

Now,

\sf Length\: of\: round\: wire =\: 160\: \times 4

\sf\bold{\red{Length\: of\: round\: wire =\: 640\: m}}

\therefore The length of wire which can go 4 times around the boundary of the plot is 640 m .


Saby123: Wonderful
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