Math, asked by omkarausarkar7718, 10 months ago

The area of a square plot is 5625 metre square . find the length of the wire that can go five times along the boundary of the plot

Answers

Answered by wwwdanielamart
2

Answer:

area = side^2

so side=sqrt(5625)=75

the perimeter of the plot is 4*75=300

we need to go around 5 times ,so 5*300=1500

therefore,the length of the required wire is 1500m

Answered by Anonymous
20

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{Given :}}

 \:\:

  • Area of a square plot is 5625 sq. m

 \:\:

 \red{\underline \bold{To \: Find:}}

 \:\:

  • Length of the wire that can go 5 times along the boundary of the plot

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

 \underline{\bold{\texttt{We know that,}}}

 \:\:

 \purple{\bold{Area \: of \: square :}}

 \:\:

 \bf \dashrightarrow side \times side

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

Area is 5625 sq. m

 \:\:

So,

 \:\:

 \sf \longmapsto side^2 = 5625

 \:\:

 \sf \longmapsto side = \sqrt { 5625 }

 \:\:

 \bf \implies side = 75 \: m

 \:\:

 \purple{\bold{Perimeter \: of \: square :}}

 \:\:

 \bf \dashrightarrow 4 \times side

 \:\:

We need the length of the wire that can go five times along the boundary of the plot.

 \:\:

So,

 \:\:

 \underline{\bold{\texttt{Length of wire will be }}}

 \:\:

 \sf \longmapsto 5(4 \times side )

 \:\:

 \sf \longmapsto 5(4 \times 75 )

 \:\:

 \sf \longmapsto 5 (300)

 \:\:

 \bf \dashrightarrow 1500 \: m

 \:\:

Hence length of wire needed will be 1500 m

\rule{200}5

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