the area of a square plot is 6084 m square. find the length of the wire which can go 4 times along the boundary of the plot.???...
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Area of the square plot =6084m
Let, side of the square plot be x
Therefore. x^2= 6084
=> x=√6084
=>x =78
Therefore side of the square = 78m.
Therefore, perimeter of the square = 4x78=312m
Therefore, length of the wire=4x312m=1248
Let, side of the square plot be x
Therefore. x^2= 6084
=> x=√6084
=>x =78
Therefore side of the square = 78m.
Therefore, perimeter of the square = 4x78=312m
Therefore, length of the wire=4x312m=1248
Answered by
2
Given that Area of square plot = 6084.
We know that Area of square = s^2
6084 = s^2
s = 78.
We know that perimeter of the square = 4 * s
= 4 * 78
= 312m.
Therefore for 1 round = 312m.
Given that length of the wire can go 4 times = 4 * 312
= 1248 m (or) 1.248 km.
Therefore the boundary of the plot = 1248m (or) 1.248km.
Hope this helps!
We know that Area of square = s^2
6084 = s^2
s = 78.
We know that perimeter of the square = 4 * s
= 4 * 78
= 312m.
Therefore for 1 round = 312m.
Given that length of the wire can go 4 times = 4 * 312
= 1248 m (or) 1.248 km.
Therefore the boundary of the plot = 1248m (or) 1.248km.
Hope this helps!
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