Question

The area of a square whose perimeter is equal to the perimeter of a rectangle with length 10 cm
breadth 6 cm is
(2) 64 cm
(b) 8 cm
(c) 16 cm
(d) 32 cm​

Answer 1

Answer:

Option-A

Step-by-step explanation:

Perimeter of square = Perimeter of rectangle

4×side = 2(l+b)

4×side = 2(10+6)

4×side = 2(16 )

4×side = 32

side = 32/4

side = 8 cm

Now area of square = side ×side

= 8×8=64 cm.

Answer 2

Step-by-step explanation:

perimeter of square = perimeter of a rectangle with length 10cm & breadth 6 cm

perimeter of the rectangle = 2(length + breadth)

= 2(10cm + 6cm)

= 2(16cm)

= 32 cm

perimeter of a square = 4×(side)

32cm = 4×(side)

(side) = 32/4 cm

(side) = 8 cm

Area of the square = (side)²

= (8cm)²

= 8cm × 8cm

= 64 cm²

Hence, the area of the square is 64 cm².