Question

the area of a square whose side is a diameter of a circle of area 4s square pi​

Answer 1

Step-by-step explanation:

64s square

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Answer 2

Given the area of a square whose sides is a diameter of a circle of area 4s square pi

We know that area of a circle = π r^2

Given area of a circle = 4s^2π

So π r^2 = 4s^2π

Now r^2 = 4s^2

So r = 2s

Given diameter = 4s

So area of a square whose side is a diameter will be l^2 = 4s × 4s = 16 s^2