Question

The area of a square whose side is a diameter of a circle of area 4s is
b) 4s
c) 16s?
d) 64s​

Answer 1

Answer:

Given The area of a square whose sides is a diameter of a circle of area 4s square pi

 We know that area of a circle = π r^2

Given area of a circle = 4s^2π

               So π r^2 = 4s^2 π

                 Now r^2 = 4s^2

               So r = 2s

Given diameter = 4s

So area of a square whose side is a diameter will be l^2 = 4s x 4s = 16 s^2

Answer 2

The answer is 16 cm sq.

It's because since the diameter of the circle is equal to the side of the square, we can say that the side of the square is 4cm.

Therefore, the area of the square becomes 4 × 4 = 16 cm sq.

Hope it helps you!