Question

The area of a squared shape room is 144m².Find the perimeter of the room,also find the cost of chips flooring of the room at the rate of Rs.25 per m².​​

Answer 1

Answer:

area of square = 144

then side =√144 = 12

perimeter of room = 4×side

=4×12= 48 m

cost of flooring= 25× area of room

=25×144 =3600Rs.

Answer 2

Step-by-step explanation:

Given:-

• The area of a square shaped room = 144m².

• Cost of flooring the room per 1m² = Rs.25

To Find:-

• The perimeter of the room.

• Cost of flooring the whole room.

Solution:-

$\sf Area \: of \: the\: square \: shaped \: room = 144m^2$

$\sf As, \: the \: area\: of \: the\: square = {Side}^{2}$

$\sf \longrightarrow {Side}^{2} = 144$

$\sf \longrightarrow Side = \sqrt{144}$

$\sf \longrightarrow Side= 12$

$\sf \therefore Side\: of \: the \: room = 12m$

$\sf Perimeter \: of \: the \: room = 4 \times side$

$\sf \; \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= 4 \times 12$

$\sf \; \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= 48m$

$\sf \therefore Perimeter \: of \: the \: room = 48m$

$\sf Cost \: of \: flooring \: per \: m^{2} = Rs.25$

$\sf Area \: of \: the \: room = 144m^2$

$\sf Cost \: of \: flooring \: the \: room = Area \times Cost \: per \: m^2$

$\sf = 144 \times 25$

$\sf = 3600$

$\underline{\boxed{\sf \therefore Total\: cost \: of \: flooring \: the \: room = Rs.3600}}$