Question

the area of a trapezium 492 sq cm if the length of its parellal sides are 13 cm and 28 cm find its height​

Answer 1

Step-by-step explanation:

answer is949 using. formula area= 1/2(a+b)* h

Answer 2

Given : The Area of Trapezium is 492 cm² and the length of it's parallel sides are 13 cm & 28 cm , respectively.

Need To Find : The Height (h) of the Trapezium .

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❍ Let's say that, the Height (h) of the Trapezium be h cm .

We're provided with the Area (Ar.) and it's parallel sides ( x & y) of Trapezium, and we'll find Height (h) of the Trapezium using Formula for Area of Trapezium .

》 Area of Trapezium is given by —

$\qquad \star\:\underline {\boxed {\pmb{\frak{ \:Area \:_{\:(Trapezium)}\:=\: \dfrac{1}{2}\:\Bigg\lgroup \: x\:+\:y\:\Bigg\rgroup h\:}}}}\:$

Where ,

• x and y are Parallel sides of Trapezium .
• h is the Height of Trapezium.
• Given Area of Trapezium is 492 cm² .

$\qquad \dag \:\underline {\frak{Substituting \:known \:Values \:in \:Formula \:\::\:}}$

$\\:\implies \sf \:Area \:_{\:(Trapezium)}\:=\: \dfrac{1}{2}\:\Bigg\lgroup \: x\:+\:y\:\Bigg\rgroup h\:$

$:\implies \sf \:492\:=\: \dfrac{1}{2}\:\Bigg\lgroup \:13 \:+\:28\:\Bigg\rgroup h\:$

$:\implies \sf \:492\:=\: \dfrac{1}{2}\:\times\:41\:\times\: h\:$

$:\implies \sf \:492\:=\: \dfrac{41}{2}\:\times\: h\:$

$:\implies \sf \:492\:=\: 20.5\:\times\: h\:$

$:\implies \sf \:492\:=\: 20.5h\:$

$:\implies \sf \:20.5h\:=\:492\:$

$:\implies \sf \:h\:=\:\cancel{\dfrac{492}{20.5}}\:$

$:\implies \pmb {\underline {\boxed {\purple {\:\frak{ \:h\:\:=\:24\:cm\:}}}}}\:\bigstar \:$

$\therefore \:\underline {\sf Hence, \:Height \:of\:Trapezium \:is\:\pmb{\sf{24\:cm\:}}\:.}$