Question

The area of a trapezium field is 240 sq m. The distance between two parallel sides is 12 m and one of the parallel side is 10 m. Find the other parallel side.
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Answer 1

Answer:

Answer

Let ABCD be a trapezium with parallel sides AB and CD

Let AB=20 ....... (Given) and CD=x

A(□ABCD)=480 m

2

,height(h)=15 m .......... (Given)

We know that, A(□ABCD)=

2

(AB+CD)

×h

⟹480=

2

20+x

×15

⟹

15

2×480

=20+x

⟹64=20+x

⟹x=44

Hence, length of other parallel side CD is 44 m.

Answer 2

${\underline{\underline{\bf{Given:}}}}$

• The area of a trapezium field = $\sf{240\:{m}^{2}}$.
• The distance between it's two parallel sides = $\sf{12\:m}$.
• The measure of one of its parallel side = $\sf{10\:m}$.

${\underline{\underline{\bf{Need\:to\:find:}}}}$

• The measure of another parallel side.

${\underline{\underline{\bf{Formula\:to\:be\:used:}}}}$

• $\underline{\boxed{\sf{{Area}_{(Trapezium)}=\frac{1}{2}\times h\times (a+b)\:sq.units}}}$

$\sf{Where,}$

• h = height
• a = parallel side (1)
• b = parallel side (2)

${\underline{\underline{\bf{Solution:}}}}$

Substituting the given measures in the formula,

$\:\:\:\:\implies{\sf{240 = \frac{1}{\cancel{2}}\times \cancel{12}\times (10+\underline{b})}}$

$\:\:\:\:\implies{\sf{240 = 6\times (10+\underline{b})}}$

$\:\:\:\:\implies{\sf{240 = 60 + \underline{6b}}}$

$\:\:\:\:\implies{\sf{240-60=\underline{6b}}}$

$\:\:\:\:\implies{\sf{180=\underline {6b}}}$

$\:\:\:\:\implies{\sf{\frac{180}{6}=\underline{b}}}$

$\:\:\:\:\implies{\sf{\red{\underline{30\:m}}=b}}$

${\underline{\underline{\bf{Final\:answer:}}}}$

• The measure of another parallel side of the trapezium field is 30 m.

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