Question

the area of a trapezium in 300 m the perpendicular distance between the two parallel side in 15 CM if the difference of the parallel side is 16 m find the length of the parallel side​

Answer 1

Solution :-

Area of trapezium is given by

$</p><p>A= \frac{1}{2} (a+b)h</p><p></p><p>$

If one side is a then the other side is a−16 since the difference of parallel sides is 16

$∴  A = \frac{1}{2} (a+a−16)×15=300 \\ \\ </p><p></p><p></p><p> \\ \\ ⇒ \frac{1}{2} (2a−16)×15=300 \\ </p><p></p><p></p><p>$

$</p><p>⇒(2a−16)×15=600</p><p></p><p>$

$</p><p>⇒(2a−16)=40  \\ [By \: dividing \: both \: side \: by \: 15]</p><p></p><p>$

2a=56

2a=56a=28 m

The other parallel side=a−16

The other parallel side=a−16a−16=28−16=12

The other parallel side=a−16a−16=28−16=12Therefore, the sides are 28m and 12m.