the area of a trapezium is 0.05 m^2 and its height is 20 cm if one of the parallel sides is longer than the other by 8 cm find the length of longer parallel side.
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Answered by
32
area=1/2×(x+x+8)cm×20cm
0.05m^2=1/2×2(x+4)cm×20cm
0.05×10000cm^2=(x+4)cm×20cm
500cm^2/20cm=x+4cm
25cm=x+4cm
x=21cm
longer parallel side=29cm.
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area= 0.05 sq.m h=20cm or 0.2m
let the smaller parallel side be x m
than the longer parallel side = (x+0.08)m
area of trapezium = 1/2× (p1+p2) ×h
0.05 =1/2 ×(x+x+0.08) ×0.2
0.05 =1/2 ×(2x+0.08) ×0.2
0.05 =1/2 ×2(x+0.04) ×0.2
0.05 =(x+0.04) ×0.2
0.05 =0.2x +0.008
0.05-0.008 =0.2x
0.042 =0.2x
0.021=x
the length of longer parallel side =0.021+0.08 =0.101m
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