The area of a trapezium is 1÷2(a^2-b^2)sq units, where 'a' and 'b' are parallel sides. Then the distance between 'a' and 'b' is units
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Answer:
a-b
Step-by-step explanation:
Area of trapezium = 1/2 × (sum of parallel sides) × height
Given, area = 1/2 (a² - b²) = 1/2 (a+b) (a-b)
Also, a and b are the parallel sides.
Therefore, sum of parallel sides= a+b
Hence, the distance between a and b is (a-b) units.
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