Question

The area of a trapezium is 105cm^2 and it's height is 7 cm if one of the parallel side is longer than the other by 6 cm find the two parallel sides

Answer 1

 



Sakshi asked in Math

the area of trapezium is 105cm2 and its height is 7 cm if 1 of the parallel sides is longer than the other side by 6 cm. find the 2 parallel sides

SHARE

 3

 Follow0

ANSWER NOW



Rupin Gore answered this
1 unhelpful votes in Math, Class X

Area of trapezium=105 sq. cm 

Height of trapezium=7 cm 

Parallel sides= x, x+6 

Area of trapezium=1/2× sum of parallel sides × height 

105 sq. cm=1/2×(x+x+6)×7 

105=1/2×2x+6×7 

2x + 6=105 × 2 
------------ 
7 

2x+6=14×2 

x + 6= 28 
--------- 
2 

x= 14 - 6 

1st side or x=8 cm 

2nd side=x+6 

= 8+6 

=14 cm

plz make me brainliest

Answer 2

Given :-
Area of trapezium = 105cm sq.
height = 7cm

(according to the question )
One of the parallel side is longer than other than by 6cm

Let one parallel side be x cm
another parallel side = (x + 6)cm

$Area \: \: of \: \: trapezium \: = \frac{1}{2} (sum \: \: of \: \: parallel \: \: sides \: ) \times heigth \\ \\ 105 = \frac{1}{2} (x + x + 6)7 \\ \\ 105 = \frac{7}{2} (2x + 6) \\ \\ 105 \times \frac{2}{7} = 2x + 6 \\ \\ 30 = 2x + 6 \\ \\ 30 - 6 = 2x \\ \\ 24 = 2x \\ \\ \frac{24}{2} = x \\ \\ 12 = x$

So, one of the parallel side = x cm = 12cm
another parallel side = (x+6)cm = 12+6 = 18cm