the area of a trapezium is 105cm^2 and its height is 7cm. If one of the parallel sides is longer than the other by 6cm. Find two parallel sides.
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area =105cm²
height=7cm
let the smaller parallel side be x
other one is x+6
area of Trapazium=1/2(sum of parallel sides) ×height
105=1/2×(x+x+6) (7)
105×2/7=2x+6
30=2x+6
2x=24
x=12
x+6=18
so two sides are of 12 cm & 18 cm
height=7cm
let the smaller parallel side be x
other one is x+6
area of Trapazium=1/2(sum of parallel sides) ×height
105=1/2×(x+x+6) (7)
105×2/7=2x+6
30=2x+6
2x=24
x=12
x+6=18
so two sides are of 12 cm & 18 cm
Answered by
3
area =105cm²
height=7cm
let the smaller parallel side be x
other one is x+6
area of Trapazium=1/2(sum of parallel sides) ×height
105=1/2×(x+x+6) (7)
105×2/7=2x+6
30=2x+6
2x=24
x=12
x+6=18
so two sides are of 12 cm & 18 cm
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