The area of a trapezium is 105cm2 and it's height is 7cm,if one of the parallel side is longer than the other by 6cm,find the two parallel sides.
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let one of the parallel sides of the trapezium be X cm
other side=x+6
height=7cm
area=105cm2
=1/2*[x+(x+6)]*7=105
=1/2*(2x+6)*7=105
=2x+6=(105*2)/7
=2x+6=210/7
=2x+6=30
=2x=30-6
=2x=23
=x=23/2
=x=11.5
therefore, one side=11.5 cm
other side=11.5+6
=17.5 cm
other side=x+6
height=7cm
area=105cm2
=1/2*[x+(x+6)]*7=105
=1/2*(2x+6)*7=105
=2x+6=(105*2)/7
=2x+6=210/7
=2x+6=30
=2x=30-6
=2x=23
=x=23/2
=x=11.5
therefore, one side=11.5 cm
other side=11.5+6
=17.5 cm
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