Question

The area of a trapezium is 105cmsquare . It's height is 7cm. If one of the parallel sides is double that of the other, find the two parallel sides.​

Answer 1

Answer:

Let the 2 parallel side be x and 2x.

Area of trapezium = 1/2 × (sum of parallel side) × height

$= > 105 = \frac{1}{2} \times (x + 2x) \times 7 \\ =>105 = \frac{7}{2} \times (x + 2x)\\ = > \frac{105 \times 2}{7} = 3x \\ = > 15 \times 2 = 3x \\ = > 30 = 3x \\ = > x = 30 \div 3 = 10 \: cm$

Therefor, x = 10 cm.

=> Side 1 = x = 10 cm

Side 2 = 2x = 20 cm

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Answer 2

Answer:

First Parallel side = 20 cm

Second Parallel side = 10 cm

Step-by-step explanation:

Height = 7 cm

Area of Trapezium = 1/2 × h × (a + b)

Where a and b are parallel sides.

In the question a is twice of b.

Then,

a = 2x

b = x

= 1/2 × 7 × (2x + x) = 105

= 7/2 (3x) = 105

3x = 105 × 2/7

3x = 15 × 2

3x = 30

x = 10

First Parallel side = 2x = 2 × 10 = 20 cm

Second Parallel side = x = 10 cm