Question

* The area of a trapezium is 1080 cm2. If the
lengths of its parallel sides are 55.6 cm and
34.4 cm, find the distance between them.​

Answer 1

Answer:

Distance between the parallel lines is 24cm

Step-by-step explanation:

Area of trapezium, A

$A = \frac{1}{2} (a + b)h$

Where a and b are lengths of parallel sides

h is height(distance between the lines)

$A = \frac{1}{2} (a + b)h \\ 1080 = \frac{1}{2}(55.6 + 34.4) \times h \\ 2160 = 90 \times h \\ h = \frac{2160}{90} = 24$

Distance between the parallel lines is 24cm

Answer 2

Step-by-step explanation:

Acc to question,

area of trapezium = 1080 cm^2 ,

Lenghts of parallel sides = 55.6 cm and 34.4 cm,

now we have to find the distance between the parallel sides,

i.e, the height of the trapezium = ?

we know, area of trapezium = 1/2* [sum of parallel sides]*height

=> 1080 = 1/2 * [ 55.6 + 34.4 ] * h

=> 1080*2 = 90.0* h

=> 2160 = 90 h

=> h = 24 cm.

Hence the distance between them is 24 cm.