The area of a trapezium is 1080 cm². If the lengths of its parallel sides are 55.6 cm and 34.4 cm, find the distance between them.
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Answered by
40
Area of trapezium = 1/2 × (a+b) × h
a and b are the parallel lengths
Now we are going to find the distance, which is height (also known as 'h').
First, substitute the given values into the equation.
1080 = 1/2 × (55.6 + 34.4) × h
Move the 1/2 over to 1080 and divide.
1080 ÷ 1/2 = (55.6 + 34.4) × h
2160 = (55.6 + 34.4) × h
Add the numbers in the brackets.
2160 = 90 × h
Move 90 over to 2160 and divide.
2160 ÷ 90 = h
24 = h
Therefore, the distance is 24cm
HOPE IT HELPS YOU
a and b are the parallel lengths
Now we are going to find the distance, which is height (also known as 'h').
First, substitute the given values into the equation.
1080 = 1/2 × (55.6 + 34.4) × h
Move the 1/2 over to 1080 and divide.
1080 ÷ 1/2 = (55.6 + 34.4) × h
2160 = (55.6 + 34.4) × h
Add the numbers in the brackets.
2160 = 90 × h
Move 90 over to 2160 and divide.
2160 ÷ 90 = h
24 = h
Therefore, the distance is 24cm
HOPE IT HELPS YOU
Answered by
24
area of trapezium =1/2*(a+b) *h
1080=1/2(55.6+34.4)h
1080=1/2*90*h
H=1080*2/90
H=24
Hope it will help you
Please mark me as brainliest
1080=1/2(55.6+34.4)h
1080=1/2*90*h
H=1080*2/90
H=24
Hope it will help you
Please mark me as brainliest
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