Question

The area of a trapezium is 110 cm squares and it’s height is 10cm.If one of the parallel sides is longer than the other by 8 cm,find the length of the two parallel sides.


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Answer 1

Answer:

the parallel sides are 23.5cm and 31.5cm

Step-by-step explanation:

area of a trapezium = $\frac{1}{2}(a+b)h$

a and b are the parallel sides

let the value of a + b be x for now

$\frac{1}{2}(x)10 = 110$

5x = 110

x = 110/5

x = 55

so a + b = 55

we were told that one of the parallel sides is longer than the other by 8cm

b = a + 8

a + b is the same as a + a + 8 = 2a + 8

2a + 8 = 55

2a = 55-8

2a = 47

a = 47/2

a = 23.5

b = a + 8

b = 23.5 + 8 = 31.5

so the paralllel sides(a and b) are 23.5cm and 31.5cm

hope this helps

pls mark as brainliest

Answer 2

Area =1/2×a+ b× 8

110=1/2×10+a×8

110=10+a× 4

110/4=10+a

27.5=10+a

27.5-10=a

17.5=a