The area of a trapezium is 119 cm' and
its altitude is 7 cm. If one of the parallel sides is longer
than the other by 8 cm, find the two parallel sides.
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Given:
The area of a trapezium = 119 cm²
Altitude (h) of the trapezium = 7cm
One of the parallel sides is longer than the other by 8 cm
To find:
Length of the two parallel sides
Solution:
Let the shorter side be x cm.
The other side will be x+8 cm
We know that area of a trapezium = 1/2 X altitude X (sum of parallel sides)
Substituting the values,
1/2 X 7 X (x + x + 8) = 119
or 7/2 (2x + 8 ) = 119
2x = 34 - 8
or x = 13 cm
So, x + 8 = 13 + 8 = 21 cm
Hence, the parallel sides of the trapezium are 13 and 21 cm long.
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