the area of a trapezium is 12 sq. m. if its height be 3 m, find the sum of its parallel sides .
Answers
Answered by
21
Hope it helps!!!!
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=>Area of trapezium=1/2(a+b) h
=>12=1/2×(a+b)3
=>(a+b)=12×2÷3
=>(a+b)=8
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#Be Brainly ✌️
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=>Area of trapezium=1/2(a+b) h
=>12=1/2×(a+b)3
=>(a+b)=12×2÷3
=>(a+b)=8
------------------------
#Be Brainly ✌️
ankit8226964288:
this answer is correct
and thanks
Answered by
63
Area of trapezium
= 1/2(sum of parallel side) * height
= 1/2(x)*3= 12
1/2*3x= 12
3x/2 = 12
3x = 24
x = 8
Sum of parallel side is 8
= 1/2(sum of parallel side) * height
= 1/2(x)*3= 12
1/2*3x= 12
3x/2 = 12
3x = 24
x = 8
Sum of parallel side is 8
wlc
and thanks
what means * ?
ok
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