Question

the area of a Trapezium is 120 m square and its height is 12 if one of the parallel side is longer than the otherby 10 metre find the length of the parallel sides​

Answer 1

since,

height of trapezium = 12 metre

let one of the parallel side of trapezium be "x".

so, other parallel side = (x + 10) metre

we know that ,

area of trapezium = $\frac{1}{2}$ × sum of parallel sides × height

=> 120 m² = $\frac{1}{\cancel{2}}$ × (x + x + 10) × $\cancel{12}$

=> 120 = 2x + 10 × 6

=> 2x + 10 = $\frac{120}{6}$

=> 2x + 10 = 20

=> 2x = 20 - 10

=> 2x = 10

=> x = $\frac{10}{2}$

=> x = 5 metre

hence ,

one of the parallel side = x = 5 metre

and , the longer parallel side = x + 10 = 5 + 10 = 15 metre

Answer 2

Here is your answer mate...


Given.:- Area = 120m^2
Height / Altitude = 12m
One parallel side = 10 m




Let the other parallel side be x ,

》 Area of trapezium = Height× (sum of parallel side) ÷2


》 120m^2 = 12m×( 10m + x ) ÷ 2

》 120m^2 = 60m + 6x

》 6x = 60m - 120m

》 6x = 60m

》 x = 60/6

》 x = 10m Ans.


So, the other parallel side is 10 m.




Hope it will help you...




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