the area of a trapezium is 12sq.m. if its height be 3m, find the sum of its parallel sied
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Answer:
8m^2
Step-by-step explanation:
we know
area=(sum of parallel sides)/2×height
ATQ,
12=(sum of parallel sides)/2×3
=>12/3×2=(sum of parallel sides)
=>8m^2=(sum of parallel sides)
Answered by
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Answer:
area of trapezium = (1/2) x (a+b) x h
h is given as 3m
so sum of its parallel side means (a+b)
12 = (1/2) x (a+b) x 3
24 = (a+b) x 3
hence, (a+b) = 8
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